Equilibrium Question 644

Question: The rate of forward reaction is two times that of reverse reaction at a given temperature and identical concentration. Kequilibrium is [KCET 2002]

Options:

A) 2.5

B) 2.0

C) 0.5

D) 1.5

Show Answer

Answer:

Correct Answer: B

Solution:

The rate of forward reaction is two times that of reverse reaction at a given temperature and identical concentration $ {K_{equilibrium}} $ is 2 because the reaction is reversible. So $ K=\frac{K_1}{K_2}=\frac{2}{1}=2 $ .



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