Equilibrium Question 644
Question: The rate of forward reaction is two times that of reverse reaction at a given temperature and identical concentration. Kequilibrium is [KCET 2002]
Options:
A) 2.5
B) 2.0
C) 0.5
D) 1.5
Show Answer
Answer:
Correct Answer: B
Solution:
The rate of forward reaction is two times that of reverse reaction at a given temperature and identical concentration $ {K_{equilibrium}} $ is 2 because the reaction is reversible. So $ K=\frac{K_1}{K_2}=\frac{2}{1}=2 $ .
