Equilibrium Question 617
Question: For the reaction $ {N_{2(g)}}+3{H_{2(g)}} $ ⇌ $ 2N{H_{3(g)}} $ , the correct expression of equilibrium constant K is [CPMT 1984, 2000]
Options:
A) $ K=\frac{{{[NH_3]}^{2}}}{[N_2]{{[H_2]}^{3}}} $
B) $ K=\frac{[N_2]{{[H_2]}^{3}}}{{{[NH_3]}^{2}}} $
C) $ K=\frac{2[NH_3]}{[N_2]\times 3[H_2]} $
D) $ K=\frac{[N_2]\times 3[H_2]}{2[NH_3]} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ K=\frac{{{[NH_3]}^{2}}}{[N_2]{{[H_2]}^{3}}} $
