Equilibrium Question 595
Question: What is the effect of increasing pressure on the dissociation of $ PCl_5 $ according to the equation $ PC{l_{5(g)}} $ ⇌ $ PC{l_{3(g)}}+C{l_{2(g)}}-x\ cal $ [UPSEAT 2004]
Options:
A) Dissociation decreases
B) Dissociation increases
C) Dissociation does not change
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ PCl_5(g) $ ⇌ $ PCl_3(g)+Cl_2(g) $ For this reaction $ \Delta n=2-1=1 $ Value of $ \Delta n $ is positive so the dissociation of $ PCl_5 $ take forward by decrease in pressure & by increase in pressure the dissociation of $ PCl_5 $ decrease.
