Equilibrium Question 595

Question: What is the effect of increasing pressure on the dissociation of $ PCl_5 $ according to the equation $ PC{l_{5(g)}} $ ⇌ $ PC{l_{3(g)}}+C{l_{2(g)}}-x\ cal $ [UPSEAT 2004]

Options:

A) Dissociation decreases

B) Dissociation increases

C) Dissociation does not change

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

$ PCl_5(g) $ ⇌ $ PCl_3(g)+Cl_2(g) $ For this reaction $ \Delta n=2-1=1 $ Value of $ \Delta n $ is positive so the dissociation of $ PCl_5 $ take forward by decrease in pressure & by increase in pressure the dissociation of $ PCl_5 $ decrease.



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