Equilibrium Question 583
Question: $ \Delta n $ , the change in the number of moles for the reaction, $ C_{12}H_{22}O_11_{(s)} $ $ +12{O_{2(g)}} $ ⇌ $ 12C{O_{2(g)}} $ $ +11H_2{O_{(l)}} $ at 25°C is [Pb. PMT 2002]
Options:
A) 0
B) 2
C) 4
D) - 1
Show Answer
Answer:
Correct Answer: A
Solution:
$ C_{12}H_{22}{O_{11(s)}}+12{O_{2(g)}}\to 12C{O_{2(g)}}+11H_2O $
$ \Delta n=12-12=0 $
