Equilibrium Question 583

Question: $ \Delta n $ , the change in the number of moles for the reaction, $ C_{12}H_{22}O_11_{(s)} $ $ +12{O_{2(g)}} $ ⇌ $ 12C{O_{2(g)}} $ $ +11H_2{O_{(l)}} $ at 25°C is [Pb. PMT 2002]

Options:

A) 0

B) 2

C) 4

D) - 1

Show Answer

Answer:

Correct Answer: A

Solution:

$ C_{12}H_{22}{O_{11(s)}}+12{O_{2(g)}}\to 12C{O_{2(g)}}+11H_2O $

$ \Delta n=12-12=0 $



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