SATHEE: Equilibrium Question 452

Equilibrium Question 452

Question: The pH of 0.1 M acetic acid is 3, the dissociation constant of acid will be

Options:

A) $1.0 \times 10^{- 4}$

B) $1.0 \times 10^{- 5}$

C) $1.0 \times 10^{- 3}$

D) $1.0 \times 10^{- 8}$

Show Answer

Answer:

Correct Answer: B

Solution:

$p H = 3$ , $[H^{+}] = 10^{- 3} M$

$∵ [H^{+}] = \sqrt{K \times c}$

${[10^{- 3}]}^{2} = K \times c$ ; $\frac{[10^{- 6}]}{0.1} = K = 10^{- 5}$

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Equilibrium Question 452

Question: The pH of 0.1 M acetic acid is 3, the dissociation constant of acid will be

Options:

Answer:

Solution:

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