Equilibrium Question 452
Question: The pH of 0.1 M acetic acid is 3, the dissociation constant of acid will be
Options:
A) $ 1.0\times {10^{-4}} $
B) $ 1.0\times {10^{-5}} $
C) $ 1.0\times {10^{-3}} $
D) $ 1.0\times {10^{-8}} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ pH=3 $ , $ [{H^{+}}]={10^{-3}}M $
$ \because [{H^{+}}]=\sqrt{K\times c} $
$ {{[{10^{-3}}]}^{2}}=K\times c $ ; $ \frac{[{10^{-6}}]}{0.1}=K={10^{-5}} $
