Equilibrium Question 433

Question: $ pH $ of a solution can be expressed as [CPMT 1999; UPSEAT 2001]

Options:

A) $ -{\log_{e}}({H^{+}}) $

B) $ -{\log_{10}}({H^{+}}) $

C) $ {\log_{e}}({H^{+}}) $

D) $ {\log_{10}}({H^{+}}) $

Show Answer

Answer:

Correct Answer: B

Solution:

$ pH=-\log [{H^{+}}] $ .



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