Equilibrium Question 433
Question: $ pH $ of a solution can be expressed as [CPMT 1999; UPSEAT 2001]
Options:
A) $ -{\log_{e}}({H^{+}}) $
B) $ -{\log_{10}}({H^{+}}) $
C) $ {\log_{e}}({H^{+}}) $
D) $ {\log_{10}}({H^{+}}) $
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Answer:
Correct Answer: B
Solution:
$ pH=-\log [{H^{+}}] $ .