Equilibrium Question 399

Question: 0.02 M monobasic acid dissociates 2% hence, $ pH $ of the solution is [MH CET 2000]

Options:

A) 0.3979

B) 1.3979

C) 1.699

D) 3.3979

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Answer:

Correct Answer: D

Solution:

$ [{H^{+}}]=\alpha .C=\frac{2}{100}\times .02 $ ; $ [{H^{+}}]=4\times {10^{-4}} $ M $ pH=-\log [{H^{+}}]=4-\log 4 $ ; $ pH=3.3979 $



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