Equilibrium Question 399
Question: 0.02 M monobasic acid dissociates 2% hence, $ pH $ of the solution is [MH CET 2000]
Options:
A) 0.3979
B) 1.3979
C) 1.699
D) 3.3979
Show Answer
Answer:
Correct Answer: D
Solution:
$ [{H^{+}}]=\alpha .C=\frac{2}{100}\times .02 $ ; $ [{H^{+}}]=4\times {10^{-4}} $ M $ pH=-\log [{H^{+}}]=4-\log 4 $ ; $ pH=3.3979 $
