Equilibrium Question 319

Question: pH of 0.1 M solution of a weak acid (HA) is 4.50. It is neutralised with $ NaOH $ solution to decrease the acid content to half pH of the resulting solution [JIPMER 2002]

Options:

A) 4.50

B) 8.00

C) 7.00

D) 10.00

Show Answer

Answer:

Correct Answer: B

Solution:

$ pH=pKa+\log \frac{[Salt]}{[Acid]} $

$ pH=pKa $

$ Ka=0.1\times {{({10^{-3.5}})}^{2}}=0.1\times {10^{-7}}={10^{-8}} $

Þ $ pH=8 $



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