Equilibrium Question 319
Question: pH of 0.1 M solution of a weak acid (HA) is 4.50. It is neutralised with $ NaOH $ solution to decrease the acid content to half pH of the resulting solution [JIPMER 2002]
Options:
A) 4.50
B) 8.00
C) 7.00
D) 10.00
Show Answer
Answer:
Correct Answer: B
Solution:
$ pH=pKa+\log \frac{[Salt]}{[Acid]} $
$ pH=pKa $
$ Ka=0.1\times {{({10^{-3.5}})}^{2}}=0.1\times {10^{-7}}={10^{-8}} $
Þ $ pH=8 $
