Equilibrium Question 318
Question: The pH of pure water or neutral solution at $ 50{}^\circ C $ is -. $ (pK_{w}=13.26 $
$ =13.26 $ at $ 50{}^\circ C) $ [Pb. PMT 2002; DPMT 2002]
Options:
A) 7.0
B) 7.13
C) 6.0
D) 6.63
Show Answer
Answer:
Correct Answer: D
Solution:
$ [{H^{+}}],[O{H^{-}}],={10^{-13.26}} $
$ \therefore $ $[{H^{+}}],=,[O{H^{-}}], $
$ \therefore $ ${{[{H^{+}}]}^{2}}={10^{-13.26}} $
$ [{H^{+}}]={10^{\frac{-13.26}{2}}} $ pH = 6.63.
