Equilibrium Question 318

Question: The pH of pure water or neutral solution at $ 50{}^\circ C $ is -. $ (pK_{w}=13.26 $

$ =13.26 $ at $ 50{}^\circ C) $ [Pb. PMT 2002; DPMT 2002]

Options:

A) 7.0

B) 7.13

C) 6.0

D) 6.63

Show Answer

Answer:

Correct Answer: D

Solution:

$ [{H^{+}}],[O{H^{-}}],={10^{-13.26}} $

$ \therefore $ $[{H^{+}}],=,[O{H^{-}}], $

$ \therefore $ ${{[{H^{+}}]}^{2}}={10^{-13.26}} $

$ [{H^{+}}]={10^{\frac{-13.26}{2}}} $ pH = 6.63.



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