Equilibrium Question 294

Question: If the solubility product of lead iodide $ (Pbl_2) $ is $ 3.2\times {10^{-8}}, $ then its solubility in moles/litre will be [MP PMT 1990]

Options:

A) $ 2\times {10^{-3}} $

B) $ 4\times {10^{-4}} $

C) $ 1.6\times {10^{-5}} $

D) $ 1.8\times {10^{-5}} $

Show Answer

Answer:

Correct Answer: A

Solution:

$ K _{sp}=4S^{3} $

$ 4S^{3}=3.2\times {10^{-8}} $ ; $ S=2\times {10^{-3}}M $ .



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