Equilibrium Question 294
Question: If the solubility product of lead iodide $ (Pbl_2) $ is $ 3.2\times {10^{-8}}, $ then its solubility in moles/litre will be [MP PMT 1990]
Options:
A) $ 2\times {10^{-3}} $
B) $ 4\times {10^{-4}} $
C) $ 1.6\times {10^{-5}} $
D) $ 1.8\times {10^{-5}} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ K _{sp}=4S^{3} $
$ 4S^{3}=3.2\times {10^{-8}} $ ; $ S=2\times {10^{-3}}M $ .
