Equilibrium Question 285

Question: pKa of acetic acid is 4.74 . The concentration of CH3COONa is 0.01 M. The pH of CH3OONa is [Orissa JEE 2004]

Options:

A) 3.37

B) 4.37

C) 4.74

D) 0.474

Show Answer

Answer:

Correct Answer: A

Solution:

H+=c,.,α=Ka,.,c

pH=log(Ka.,c)1/2

=12[logKalogc]

=12[4.74log102]

=12[4.74+2]=3.37 .



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