Equilibrium Question 285

Question: $ pK_{a} $ of acetic acid is $ 4.74 $ . The concentration of $ CH_3COONa $ is 0.01 M. The pH of $ CH_3OONa $ is [Orissa JEE 2004]

Options:

A) 3.37

B) 4.37

C) 4.74

D) 0.474

Show Answer

Answer:

Correct Answer: A

Solution:

$ {H^{+}}=c,.,\alpha =\sqrt{K_{a},.,c} $

$ pH=-\log {{( \sqrt{K_{a}.,c} )}^{1/2}} $

$ =\frac{1}{2}[-\log K_{a}-\log c] $

$ =\frac{1}{2}[4.74-\log {10^{-2}}] $

$ =\frac{1}{2}[4.74+2]=3.37 $ .



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