Equilibrium Question 246
Question: The solubility product of a sparingly soluble salt $ AX_2 $ is $ 3.2\times {10^{-11}} $ . Its solubility (in moles / litres) is [CBSE PMT 2004]
Options:
A) $ 2\times {10^{-4}} $
B) $ 4\times {10^{-4}} $
C) $ 5.6\times {10^{-6}} $
D) $ 3.1\times {10^{-4}} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ AX_2\to \underset{x}{\mathop{A}},\ \ +\ \ \underset{2x}{\mathop{2X}}, $
$ K _{sp}=4x^{3} $ ; $ x=\sqrt[3]{\frac{3.2\times {10^{-11}}}{4}} $ ; $ x=2\times {10^{-4}} $ mole/litre.
