Equilibrium Question 246

Question: The solubility product of a sparingly soluble salt $ AX_2 $ is $ 3.2\times {10^{-11}} $ . Its solubility (in moles / litres) is [CBSE PMT 2004]

Options:

A) $ 2\times {10^{-4}} $

B) $ 4\times {10^{-4}} $

C) $ 5.6\times {10^{-6}} $

D) $ 3.1\times {10^{-4}} $

Show Answer

Answer:

Correct Answer: A

Solution:

$ AX_2\to \underset{x}{\mathop{A}},\ \ +\ \ \underset{2x}{\mathop{2X}}, $

$ K _{sp}=4x^{3} $ ; $ x=\sqrt[3]{\frac{3.2\times {10^{-11}}}{4}} $ ; $ x=2\times {10^{-4}} $ mole/litre.



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