Equilibrium Question 243
Question: Solubility product of $ AgCl $ is $ 1\times {10^{-6}} $ at 298 K. Its solubility in mole $ litr{e^{-1}} $ would be [Pb.CET 2001]
Options:
A) $ 1\times {10^{-6}}mol/litre $
B) $ 1\times {10^{-3}}mol/litre $
C) $ 1\times {10^{-12}}mol/litre $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
For $ AgCl\to \underset{x}{\mathop{A{g^{+}}}},+\underset{x}{\mathop{C{l^{-}}}}, $
$ K _{sp}=x^{2} $ ; $ x=\sqrt{K _{sp}} $ , $ \sqrt{1\times {10^{-6}}}=1\times {10^{-3}}mole/litre $ .
