Equilibrium Question 243

Question: Solubility product of $ AgCl $ is $ 1\times {10^{-6}} $ at 298 K. Its solubility in mole $ litr{e^{-1}} $ would be [Pb.CET 2001]

Options:

A) $ 1\times {10^{-6}}mol/litre $

B) $ 1\times {10^{-3}}mol/litre $

C) $ 1\times {10^{-12}}mol/litre $

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

For $ AgCl\to \underset{x}{\mathop{A{g^{+}}}},+\underset{x}{\mathop{C{l^{-}}}}, $

$ K _{sp}=x^{2} $ ; $ x=\sqrt{K _{sp}} $ , $ \sqrt{1\times {10^{-6}}}=1\times {10^{-3}}mole/litre $ .



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