Equilibrium Question 243

Question: Solubility product of AgCl is 1×106 at 298 K. Its solubility in mole litre1 would be [Pb.CET 2001]

Options:

A) 1×106mol/litre

B) 1×103mol/litre

C) 1×1012mol/litre

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

For AgClAg+x,+Clx,

Ksp=x2 ; x=Ksp , 1×106=1×103mole/litre .



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