Equilibrium Question 228
Question: Why pure $ NaCl $ is precipitated when $ HCl $ gas is passed in a saturated solution of $ NaCl $ [NCERT 1977; MP PMT 1987; CPMT 1974, 78, 81]
Options:
A) Impurities dissolves in $ HCl $
B) The value of $ [N{a^{+}}] $ and $ [C{l^{-}}] $ becomes smaller than $ K _{sp} $ of $ NaCl $
C) The value of $ [N{a^{+}}] $ and $ [C{l^{-}}] $ becomes greater than $ K _{sp} $ of $ NaCl $
D) $ HCl $ dissolves in the water
Show Answer
Answer:
Correct Answer: C
Solution:
$ NaC{l_{(s)}} $ ⇌ $ N{a^{+}} _{(aq)}+C{l^{-}} _{(aq)} $
$ HCl $ ⇌ $ {H^{+}}+C{l^{-}} $ The increase in $ [C{l^{-}}] $ brings in an increase in $ [N{a^{+}}] $
$ [C{l^{-}}] $ which will lead for backward reaction because $ K _{sp},NaCl=[N{a^{+}}][C{l^{-}}] $ .
