SATHEE: Equilibrium Question 228

Equilibrium Question 228

Question: Why pure $N a C l$ is precipitated when $H C l$ gas is passed in a saturated solution of $N a C l$ [NCERT 1977; MP PMT 1987; CPMT 1974, 78, 81]

Options:

A) Impurities dissolves in $H C l$

B) The value of $[N a^{+}]$ and $[C l^{-}]$ becomes smaller than $K_{s p}$ of $N a C l$

C) The value of $[N a^{+}]$ and $[C l^{-}]$ becomes greater than $K_{s p}$ of $N a C l$

D) $H C l$ dissolves in the water

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Answer:

Correct Answer: C

Solution:

$N a C l_{(s)}$ ⇌ $N {a^{+}}_{(a q)} + C {l^{-}}_{(a q)}$

$H C l$ ⇌ $H^{+} + C l^{-}$ The increase in $[C l^{-}]$ brings in an increase in $[N a^{+}]$

$[C l^{-}]$ which will lead for backward reaction because $K_{s p}, N a C l = [N a^{+}] [C l^{-}]$ .

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Equilibrium Question 228

Question: Why pure NaCl is precipitated when HCl gas is passed in a saturated solution of NaCl [NCERT 1977; MP PMT 1987; CPMT 1974, 78, 81]

Options:

Answer:

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Question: Why pure $N a C l$ is precipitated when $H C l$ gas is passed in a saturated solution of $N a C l$ [NCERT 1977; MP PMT 1987; CPMT 1974, 78, 81]