Equilibrium Question 228

Question: Why pure $ NaCl $ is precipitated when $ HCl $ gas is passed in a saturated solution of $ NaCl $ [NCERT 1977; MP PMT 1987; CPMT 1974, 78, 81]

Options:

A) Impurities dissolves in $ HCl $

B) The value of $ [N{a^{+}}] $ and $ [C{l^{-}}] $ becomes smaller than $ K _{sp} $ of $ NaCl $

C) The value of $ [N{a^{+}}] $ and $ [C{l^{-}}] $ becomes greater than $ K _{sp} $ of $ NaCl $

D) $ HCl $ dissolves in the water

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Answer:

Correct Answer: C

Solution:

$ NaC{l_{(s)}} $ ⇌ $ N{a^{+}} _{(aq)}+C{l^{-}} _{(aq)} $

$ HCl $ ⇌ $ {H^{+}}+C{l^{-}} $ The increase in $ [C{l^{-}}] $ brings in an increase in $ [N{a^{+}}] $

$ [C{l^{-}}] $ which will lead for backward reaction because $ K _{sp},NaCl=[N{a^{+}}][C{l^{-}}] $ .



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