Equilibrium Question 202

Question: If the solubility product of $ BaSO_4 $ is $ 1.5\times {10^{-9}} $ in water, its solubility in moles per litre, is [BHU 1995; MP PET 1995; UPSEAT 204]

Options:

A) $ 1.5\times {10^{-9}} $

B) $ 3.9\times {10^{-5}} $

C) $ 7.5\times {10^{-5}} $

D) $ 1.5\times {10^{-5}} $

Show Answer

Answer:

Correct Answer: B

Solution:

$ BaSO_4 $ ⇌ $ B{a^{2+}}+SO_4^{-,-} $ Solubility constant $ =S\times S $

$ 1.5\times {10^{-19}}=S^{2} $ ; $ S=\sqrt{1.5\times {10^{-19}}} $ ; $ S=3.9\times {10^{-5}} $



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