Equilibrium Question 202
Question: If the solubility product of $ BaSO_4 $ is $ 1.5\times {10^{-9}} $ in water, its solubility in moles per litre, is [BHU 1995; MP PET 1995; UPSEAT 204]
Options:
A) $ 1.5\times {10^{-9}} $
B) $ 3.9\times {10^{-5}} $
C) $ 7.5\times {10^{-5}} $
D) $ 1.5\times {10^{-5}} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ BaSO_4 $ ⇌ $ B{a^{2+}}+SO_4^{-,-} $ Solubility constant $ =S\times S $
$ 1.5\times {10^{-19}}=S^{2} $ ; $ S=\sqrt{1.5\times {10^{-19}}} $ ; $ S=3.9\times {10^{-5}} $
