Equilibrium Question 174
Question: Solubility product of $ BaCl_2 $ is $ 4\times {10^{-9}} $ . Its solubility in moles/litre would be [AFMC 1982; Roorkee 1990; BHU 2000]
Options:
A) $ 1\times {10^{-3}} $
B) $ 1\times {10^{-9}} $
C) $ 4\times {10^{-27}} $
D) $ 1\times {10^{-27}} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ K _{sp}=4S^{3}, $
$ S^{3}=\frac{4\times {10^{-9}}}{4}={10^{-9}} $
$ \therefore ,S={10^{-3}}M $ .
