SATHEE: Equilibrium Question 174

Equilibrium Question 174

Question: Solubility product of $B a C l_{2}$ is $4 \times 10^{- 9}$ . Its solubility in moles/litre would be [AFMC 1982; Roorkee 1990; BHU 2000]

Options:

A) $1 \times 10^{- 3}$

B) $1 \times 10^{- 9}$

C) $4 \times 10^{- 27}$

D) $1 \times 10^{- 27}$

Show Answer

Answer:

Correct Answer: A

Solution:

$K_{s p} = 4 S^{3},$

$S^{3} = \frac{4 \times 10^{- 9}}{4} = 10^{- 9}$

$∴, S = 10^{- 3} M$ .

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Equilibrium Question 174

Question: Solubility product of BaCl2 is 4×10−9 . Its solubility in moles/litre would be [AFMC 1982; Roorkee 1990; BHU 2000]

Options:

Answer:

Solution:

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Question: Solubility product of $B a C l_{2}$ is $4 \times 10^{- 9}$ . Its solubility in moles/litre would be [AFMC 1982; Roorkee 1990; BHU 2000]