Equilibrium Question 162

Question: The solubility of silver chromate in 0.01 M K2CrO4 is 2×10−8mol,dm−3 . The solubility product of silver chromate will be [MH CET 2000]

Options:

A) 8×10−24

B) 16×10−24

C) 1.6×10−18

D) 16×10−18

Show Answer

Answer:

Correct Answer: D

Solution:

Ksp=[Ag+]2[Cro4−,−]=[2S]2[0.01] = 4S2[0.01]=4[2×10−8]2×0.01

=16×10−18 .

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