Equilibrium Question 162
Question: The solubility of silver chromate in 0.01 M $ K_2CrO_4 $ is $ 2\times {10^{-8}}mol,d{m^{-3}} $ . The solubility product of silver chromate will be [MH CET 2000]
Options:
A) $ 8\times {10^{-24}} $
B) $ 16\times {10^{-24}} $
C) $ 1.6\times {10^{-18}} $
D) $ 16\times {10^{-18}} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ K _{sp}={{[A{g^{+}}]}^{2}}[Cro_4^{-,-}]={{[2S]}^{2}}[0.01] $ = $ 4S^{2}[0.01]=4{{[2\times {10^{-8}}]}^{2}}\times 0.01 $
$ =16\times {10^{-18}} $ .
