Equilibrium Question 150

Question: If the solubility product Ksp of a sparingly soluble salt MX2 at 25∘C is 1.0×10−11 , the solubility of the salt in mole litre-1 at this temperature will be [RPMT 2000]

Options:

A) 2.46×1014

B) 1.36×10−4

C) 2.60×10−7

D) 1.20×10−10

Show Answer

Answer:

Correct Answer: B

Solution:

MX2 ⇌ M+(S),,+2X−(2S)2, ; Ksp=4S3

S=Ksp43=1×10−1143=1.35×10−4

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