Equilibrium Question 150

Question: If the solubility product $ K _{sp} $ of a sparingly soluble salt $ MX_2 $ at $ 25{}^\circ C $ is $ 1.0\times {10^{-11}} $ , the solubility of the salt in mole litre-1 at this temperature will be [RPMT 2000]

Options:

A) $ 2.46\times 10^{14} $

B) $ 1.36\times {10^{-4}} $

C) $ 2.60\times {10^{-7}} $

D) $ 1.20\times {10^{-10}} $

Show Answer

Answer:

Correct Answer: B

Solution:

$ MX_2 $ ⇌ $ \underset{(S),}{\mathop{{M^{+}}}},+\underset{{{(2S)}^{2}}}{\mathop{2{X^{-}}}}, $ ; $ K _{sp}=4S^{3} $

$ S=\sqrt[3]{\frac{K _{sp}}{4}}=\sqrt[3]{\frac{1\times {10^{-11}}}{4}}=1.35\times {10^{-4}} $



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