D-And F-Block Elements Ques 74

Question: The correct order of magnetic moments (spin only values in B.M.) among is

[AIEEE 2004]

Options:

A) $ {{[Fe{{(CN)}_6}]}^{4-}}>{{[MnCl_4]}^{2-}}>{{[CoCl_4]}^{2-}} $

B) $ {{[MnCl_4]}^{2-}}>{{[Fe{{(CN)}_6}]}^{4-}}>{{[CoCl_4]}^{2-}} $

C) $ {{[MnCl_4]}^{2-}}>{{[CoCl_4]}^{2-}}>{{[Fe{{(CN)}_6}]}^{4-}} $

D) $ {{[Fe{{(CN)}_6}]}^{4-}}>{{[CoCl_4]}^{2-}}>{{[MnCl_4]}^{2-}} $ (Atomic nos. $ Mn=25,,Fe=26,,Co=27 $ )

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Answer:

Correct Answer: C

Solution:

Magnetic moment $ =\sqrt{n+2} $ Where, n = number of unpaired electron i.e., greater the number of unpaired electron greater will be the paramagnetic character.



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