D-And F-Block Elements Ques 74
Question: The correct order of magnetic moments (spin only values in B.M.) among is
[AIEEE 2004]
Options:
A) $ {{[Fe{{(CN)}_6}]}^{4-}}>{{[MnCl_4]}^{2-}}>{{[CoCl_4]}^{2-}} $
B) $ {{[MnCl_4]}^{2-}}>{{[Fe{{(CN)}_6}]}^{4-}}>{{[CoCl_4]}^{2-}} $
C) $ {{[MnCl_4]}^{2-}}>{{[CoCl_4]}^{2-}}>{{[Fe{{(CN)}_6}]}^{4-}} $
D) $ {{[Fe{{(CN)}_6}]}^{4-}}>{{[CoCl_4]}^{2-}}>{{[MnCl_4]}^{2-}} $ (Atomic nos. $ Mn=25,,Fe=26,,Co=27 $ )
Show Answer
Answer:
Correct Answer: C
Solution:
Magnetic moment $ =\sqrt{n+2} $ Where, n = number of unpaired electron i.e., greater the number of unpaired electron greater will be the paramagnetic character.
