SATHEE: D-And F-Block Elements Ques 30

D-And F-Block Elements Ques 30

Question: The equivalent weight of $K_{2} C r_{2} O_{7}$ in acidic medium

Options:

A) 294

B) 298

C) 49

D) 50

Show Answer

Answer:

Correct Answer: C

Solution:

$K_{2} C r_{2} O_{7} + 3 H_{2} S O_{4}, \to K_{2} S O_{4} + C r_{2} {(S O_{4})}_{3} + 3, (O) + 3 H_{2}$ No. of electrons lossed = 12 - 6 = 6 \ Equivalent weight = $\frac{M}{6} = \frac{294}{6} = 49.$

D-And F-Block Elements Ques 30

Question: The equivalent weight of $K_{2} C r_{2} O_{7}$ in acidic medium

Options:

Answer:

Solution:

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D-And F-Block Elements Ques 30

Question: The equivalent weight of K2Cr2O7 in acidic medium

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: The equivalent weight of $K_{2} C r_{2} O_{7}$ in acidic medium