A) 294
B) 298
C) 49
D) 50
Correct Answer: C
$ K_2Cr_2O_7+3H_2SO_4,\to K_2SO_4+Cr_2{{(SO_4)}_3}+3,(O)+3H_2 $ No. of electrons lossed = 12 - 6 = 6 \ Equivalent weight = $ \frac{M}{6}=\frac{294}{6}=49. $
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