Chemical Thermodynamics Question 57

Question: A process is taking place at constant temperature and pressure. Then [KCET 2004]

Options:

A) $ \Delta H=\Delta E $

B) $ \Delta H=T\Delta S $

C) $ \Delta H=0 $

D) $ \Delta S=0 $

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Answer:

Correct Answer: B

Solution:

$ \Delta G=\Delta H-T\Delta S $ at constant temperature and pressure $ \Delta G=0 $

$ 0=\Delta T-T\Delta S $ so $ \Delta H=T\Delta S $



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