Chemical Thermodynamics Question 57
Question: A process is taking place at constant temperature and pressure. Then [KCET 2004]
Options:
A) $ \Delta H=\Delta E $
B) $ \Delta H=T\Delta S $
C) $ \Delta H=0 $
D) $ \Delta S=0 $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \Delta G=\Delta H-T\Delta S $ at constant temperature and pressure $ \Delta G=0 $
$ 0=\Delta T-T\Delta S $ so $ \Delta H=T\Delta S $
