Chemical Thermodynamics Question 445

Question: Combustion of glucose takes place according to the equation,$ C_6H_{12}O_6+6O_2\to 6CO_2+6H_2O $ , $ \Delta H=-72,kcal $ .How much energy will be required for the production of 1.6 g of glucose (Molecular mass of glucose = 180 g)

Options:

A) 0.064 kcal

B) 0.64 kcal

C) 6.4 kcal

D) 64 kcal

Show Answer

Answer:

Correct Answer: B

Solution:

  • $ \Delta H,per,1.6g=\frac{72\times 1.6}{180}=0.64,kcal $ .


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