Chemical Thermodynamics Question 445
Question: Combustion of glucose takes place according to the equation,$ C_6H_{12}O_6+6O_2\to 6CO_2+6H_2O $ , $ \Delta H=-72,kcal $ .How much energy will be required for the production of 1.6 g of glucose (Molecular mass of glucose = 180 g)
Options:
A) 0.064 kcal
B) 0.64 kcal
C) 6.4 kcal
D) 64 kcal
Show Answer
Answer:
Correct Answer: B
Solution:
- $ \Delta H,per,1.6g=\frac{72\times 1.6}{180}=0.64,kcal $ .
