Chemical Thermodynamics Question 410

Question: Temperature of 5 moles of a gas is decreased by 2K at constant pressure. Indicate the correct statement

Options:

A) Work done by gas is = 5 R

B) Work done over the gas is = 10 R

C) Work done by the gas = 10 R

D) Work done =0

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Answer:

Correct Answer: B

Solution:

  • For 5 moles of gas at temperature T, PV1=5RT For 5 moles of gas at temperature T2 , PV2=5R(T2)

P(V2V1)=5R(T2T);

PΔV=10R,

PΔV=10R When ΔV is negative, W is + ve.



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