Chemical Thermodynamics Question 410

Question: Temperature of 5 moles of a gas is decreased by 2K at constant pressure. Indicate the correct statement

Options:

A) Work done by gas is = 5 R

B) Work done over the gas is = 10 R

C) Work done by the gas = 10 R

D) Work done =0

Show Answer

Answer:

Correct Answer: B

Solution:

  • For 5 moles of gas at temperature T, $ PV_1=5RT $ For 5 moles of gas at temperature $ T-2 $ , $ PV_2=5R( T-2 ) $

$ \therefore P(V_2-V_1)=5R( T-2-T ); $

$ P\Delta V=-10R, $

$ -P\Delta V=10R $ When $ \Delta V $ is negative, W is + ve.



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