Chemical Thermodynamics Question 404

Question: 0.5 mole each of two ideal gases $ A( {C_{v,m}}=\frac{5}{2}R ) $ and $ B({C_{v,m}}=3R) $ are taken in a container and expanded reversibly and adiabatically, during this process temperature of gaseous mixture decreased from 350 K to 250 K. Find $ \Delta H $ (in cal/mol) for the process:

Options:

A) $ -100R $

B) $ -137.5R $

C) $ -375R $

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

  • $ \Delta H=(n_1{C_{p,m_1}}+n_2{C_{p,m_2}})\Delta T $

$ =( 0.5\times \frac{7}{2}R+0.5\times 4R )(-100) $

$ =-375R $



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