Chemical Thermodynamics Question 404
Question: 0.5 mole each of two ideal gases $ A( {C_{v,m}}=\frac{5}{2}R ) $ and $ B({C_{v,m}}=3R) $ are taken in a container and expanded reversibly and adiabatically, during this process temperature of gaseous mixture decreased from 350 K to 250 K. Find $ \Delta H $ (in cal/mol) for the process:
Options:
A) $ -100R $
B) $ -137.5R $
C) $ -375R $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
- $ \Delta H=(n_1{C_{p,m_1}}+n_2{C_{p,m_2}})\Delta T $
$ =( 0.5\times \frac{7}{2}R+0.5\times 4R )(-100) $
$ =-375R $
