Chemical Thermodynamics Question 395

Question: One mole of solid iron was vaporized in an oven at its boiling point of 3433 K and enthalpy of vaporization of iron is $ 344.3kJmo{{l}^{-1}} $ . The value of entropy vaporization (in J $ mo{{l}^{-1}} $ ) of iron is

Options:

A) 100

B) 10

C) $ -100 $

D) 110

Show Answer

Answer:

Correct Answer: A

Solution:

  • $ \Delta S=\frac{\Delta H}{T}=\frac{334.3\times 10^{3}}{3443}=100Jmo{{l}^{-1}} $


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