Chemical Thermodynamics Question 395
Question: One mole of solid iron was vaporized in an oven at its boiling point of 3433 K and enthalpy of vaporization of iron is $ 344.3kJmo{{l}^{-1}} $ . The value of entropy vaporization (in J $ mo{{l}^{-1}} $ ) of iron is
Options:
A) 100
B) 10
C) $ -100 $
D) 110
Show Answer
Answer:
Correct Answer: A
Solution:
- $ \Delta S=\frac{\Delta H}{T}=\frac{334.3\times 10^{3}}{3443}=100Jmo{{l}^{-1}} $
