SATHEE: Chemical Thermodynamics Question 376

Chemical Thermodynamics Question 376

Question: The enthalpy of neutralisation of $N H_{4} O H$ and $C H_{3} C O O H$ is $- 10.5 k c a l m o l^{- 1}$ and enthalpy of neutralisation of $C H_{3} C O O H$ with strong base is $- 12.5, k c a l m o l^{- 1}$ . The enthalpy of ionisation of $N H_{4} O H$ will be

Options:

A) $3.2 k c a l m o l^{- 1}$

B) $2.0 k c a l m o l^{- 1}$

C) $3.0 k c a l m o l^{- 1}$

D) $4.0 k c a l m o l^{- 1}$

Show Answer

Answer:

Correct Answer: B

Solution:

$Δ_{n e u} H$ for strong base and strong acid $= - 13.7 k c a l, e q^{- 1}$

$Δ H_{i o n} (C H_{3} C O O H)$

$= - 12.5 - (- 13.7) = 1.2 k c a l m o l^{- 1}$

$Δ H_{i o n} (N H_{4} O H)$

$= - 10.5 - (- 13.7) - Δ H_{i o n} (C H_{3} C O O H)$

$= 13.7 - 10.5 - 1.2$

$= 2 k c a l, m o l^{- 1}$

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Chemical Thermodynamics Question 376

Question: The enthalpy of neutralisation of NH4OH and CH3COOH is −10.5kcalmol−1 and enthalpy of neutralisation of CH3COOH with strong base is −12.5,kcalmol−1 . The enthalpy of ionisation of NH4OH will be

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Question: The enthalpy of neutralisation of $N H_{4} O H$ and $C H_{3} C O O H$ is $- 10.5 k c a l m o l^{- 1}$ and enthalpy of neutralisation of $C H_{3} C O O H$ with strong base is $- 12.5, k c a l m o l^{- 1}$ . The enthalpy of ionisation of $N H_{4} O H$ will be